Does any one know where I can find out what pressure is necessary
to cut 14 gauge silver?
It is difficult to give precise number, since there are many
variables, but to illustrate the calculations to arrive at some
indication of the force required we can proceed as follows:
Shear strength of silver (it is alloy and annealing state dependent)
we can assume for argument sake to be 11000 psi. This is the force
required to give start to shearing fracture. More pressure would be
required to extend the fracture through the thickness of the metal.
If you are using a punch of 1 inch diameter, the area of contact
with metal would be 3.14158 * (1/2)^2 = 0.79 square inches. Multiply
by shear strength and initial pressure would be 8639 pounds. For all
practical purpose a 1000 pounds would do it.
However 2 inch punch would require 34,558 pounds of initial pressure
and in a real world 40,000 would be closer to the truth. 14 gauge
would definitely require more force. Also condition of the punch
face, misalignment, and many other factors could increase these